# This software carries the following license:
#
# Modified BSD license
#
# Redistribution and use in source and binary forms, with or without
# modification, are permitted provided that the following conditions are met:
#
# 1. Redistributions of source code must retain the above copyright notice,
# this list of conditions and the following disclaimer.
#
# 2. Redistributions in binary form must reproduce the above copyright notice,
# this list of conditions and the following disclaimer in the documentation
# and/or other materials provided with the distribution.
#
# 3. The name of the author may not be used to endorse or promote products
# derived from this software without specific prior written permission.
#
# THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR IMPLIED
# WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF
# MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO
# EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
# SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO,
# PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS;
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#
# Steinar Knutsen
import string
def findnum(start, haystack):
start = start + 1
while start <= len(haystack)-1:
if not haystack[start] in string.digits:
break
start = start + 1
return start
def numcompare(x, y):
i0 = i1 = -1
while i0 < len(x)-1 and i1 < len(y)-1:
i0, i1 = i0 + 1, i1 + 1
if x[i0] in string.digits and y[i0] in string.digits:
endx, endy = findnum(i0, x), findnum(i1, y)
X, Y = string.atol(x[i0:endx]), string.atol(y[i1:endy])
if X != Y:
return cmp(X, Y)
else:
i0, i1 = endx-1, endy-1
continue
if x[i0] != y[i1]:
return cmp(x[i0], y[i1])
return cmp(x, y)